To be able to see a measurable effect, your boiling point elevation must be at least 1.00°C. Knowing that the Kb­ of water is 0.512\frac{^\circ\text{C}\cdot\text {kg}}{\text{mol}}0.512 ∘ C ⋅ kg mol, determine what mass of calcium chloride (in g) is needed to see at least a 1.00^\circ\text{C}1.00 ∘ C boiling point increase in 26.63 mL of water.

Answer : The mass of calcium chloride (in g) needed is, 1.92 grams.

Explanation : Given,

Boiling point of elevation constant for water =

Mass of water (solvent) =

Molar mass of = 110.98 g/mole

Formula used :  

where,

= change in boiling point  =

i = Van't Hoff factor = 3 (for electrolyte)

= boiling point constant for water

m = molality

Now put all the given values in this formula, we get

Therefore, the mass of calcium chloride (in g) needed is, 1.92 grams.

1.solid

2.carbon dioxide

3.helium

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.