What is the pOH of a KOH solution that has [OH− ] = 5.81 × 10−3 M?

The pOH of the KOH solution is 2, 24.

Explanation:

The pOH is a measure of the concentration of OH (hydroxyl) ions in the solution.

The pOH is calculated as :

pOH = -log (OH-)= -log ( 5.81 × 10−3 M)= 2,24.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.