The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution containing the four anions, each at a concentration of 0.10 M, in what order would they precipitate?Compound:
a. AgCl ksp: 1.8x10^-10
b. Ag_2_CrO_4_ksp: 1.1 x 10 ^-12
c. AgBrksp: 5.4 x10 ^ -13
d. AgIksp: 8.5 x 10 ^ -17

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

Where X is cation and Y is anion.

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. Where X is the solubility of the compound.

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

= 1.34x10⁻⁵M

= 6.50x10⁻⁵M

= 7.35x10⁻⁷M

= 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

AgI, AgBr, AgCl and Ag₂CrO₄

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .