A sample of gas occupies 2.30 L at 1.086 atm and 70°C. What is its

volume at STP?

2 L

Explanation:

Given data:

Initial volume of gas = 2.30 L

Initial temperature = 1.086 atm

Initial temperature = 70°C (70+273 =343 k)

Final volume = ?

Final temperature = standard = 273 K

Final pressure = standard = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

now we will put the values.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.086 atm ×2.30 L ×273 K / 343 K × 1 atm

V₂ = 681.9 atm.L.K  / 343 K . atm

V₂ = 2 L

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer