F 100. grams of liquid water at 100.°C and 200. grams of water at 20.0°C are mixed in an insulated container, what will the final temperature of the mixture be? (Specific heat capacity of H 2O( ℓ) = 4.18 J/g•K)

Answer : The final temperature of the mixture will be,

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= = specific heat of liquid water = Same

= mass of liquid water = 100 g

= mass of water  = 200 g

= final temperature of mixture = ?

= initial temperature of liquid water =

= initial temperature of water =

Now put all the given values in the above formula, we get

Therefore, the final temperature of the mixture will be,

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.