How many sulfur atoms would be present in 41.8 moles of sulfur?

An atom is the smallest unit of ordinary matter that forms a chemical element.

There are atoms of sulphur are contained in 41.8 g of sulphur

The data is as given:-

The formula we will use is.

So, according to the formula the number of moles of sulphur =

Therefore, In 1 mole of atoms, there is  number of atoms.

So, In 1.30625 moles of Sulphur atom, number of atoms =

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7 .86×10^23 atoms of sulphur are contained in 41.8 g of sulphur

Explanation:

Molar mass of sulphur = 32 g/mol

Given mass of sulphur = 41.8g

Number of moles = Given mass / Molar Mass

So, number of moles of sulphur = 41.8/32 = 1.30625 moles

We know that,

In 1 mole of atom there are 6.022 × 10^23 number of atoms.

So, In 1.30625 moles of Sulphur arom, number of atoms = 1.30625 × 6.022 × 10^23 = 7.86×10^23 atoms

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