H2(g) + F2(g) → 2 HF(g) ΔH=-546 kJ
According to the Law of Conservation of Energy, what does this equation tell us about the change in energy?
A) It took 546 kJ of energy to form HF.
B) 546 kJ of energy were added to the system in order for the reaction to proceed.
C) More energy was required to break the bonds of H2 and F2 than was released in the formation of 2 HF bonds.
D) More energy was released in the formation of the 2 HF bonds than in the breaking of the bonds of H2 and F2.

The answer is D, More energy was released in the formation of the 2 HF bonds than in the breaking of the bonds of H2 and F2.

Explanation: Honestly, I guessed on this question and got it right, but I see that right after the arrow on the right side of the equation, there's a 2 in front of the HF(g). On the left side of the equation, it does not match the right side, which led me to believe that there was more energy being released.

i think the answer is terrae but not 100 percent sure. ▓▬▬ §

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24