If a sample of neon gas at 25.00∘C and 0.500 atm is heated at a constant volume until the pressure is 0.850 atm, what must be the final temperature of the gas in Kelvin?

T₂ = 506.6 K

Explanation:

Given data:

Initial pressure of gas = 25°C (25+273 =298 K)

Initial temperature = 0.500 atm

Final pressure = 0.850 atm

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.500 atm / 298 K = 0.850 atm /T₂

T₂ = 0.850 atm × 298 K / 0.500 atm

T₂ = 253.3 atm. K / 0.500 atm

T₂ = 506.6 K