What’s the PH and OH- of 6.0 x 10^-10?

The answer to your question is pH = 9.2;  [OH] = 1.58 x 10⁻⁵

Explanation:

Data

[H⁺] = 6.0 x 10⁻¹⁰ M

pH = ?

pH definition. pH measures the hydrogen concentration. pH measures the acidity and the alkalinity of a solution. A solution is acid if the pH goes from 0 to 6.9, a neutral solution has a pH of 7 and an alkali solution has a pH from 7.1 to 14.

pOH measures the [OH⁻] concentration

Formula

             pH = -log[H⁺]

             pH + pOH = 14

-Substitution

            pH = -log[6 x 10⁻¹⁰]

-Simplification

            pH = - (-9.2)

            pH = 9.2

-Calculate pOH

            pOH = 14 - pH

            pOH = 14 - 9.2

            pOH = 4.8      

-Calculate the concentration of OH⁻

           pOH = -log[OH⁻]

           [OH⁻] = -antilog4.8

           [OH] = 1.58 x 10⁻⁵      

law of conservation of matter

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"