Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g)CO2(g)+CCl4 (g)⇌2COCl2(g) Calculate ΔGΔG for this reaction at 25 ∘C∘C under these conditions: PCO2PCCl4PCOCl2===0.140atm0.185atm0 .740atmPCO2=0.140atmPCCl4=0.185atmP COCl2=0.740atm ΔG∘fΔGf∘ for CO2(g)CO2(g) is −394.4kJ/mol−394.4kJ/mol, ΔG∘fΔGf∘ for CCl4(g)CCl4(g) is −62.3kJ/mol−62.3kJ/mol, and ΔG∘fΔGf∘ for COCl2(g)COCl2(g) is −204.9kJ/mol−204.9kJ/mol.

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.