How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? show all of the work used to find your answer.

ca + cl2 cacl2

The balanced chemical reaction is:

Ca + Cl2 =  CaCl2

We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.

56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction

Only one reactant yields 2 or more products. meaning you will only have 1 product and it will break down into 2 or more products. eg. h2o -> h2 + o2