How many milliliters of 4.8 M NaOH are needed to exactly neutralize 29 milliliters of 2 M HCl?

V₁ = 12.1 mL

Explanation:

Given data:

Volume of NaOH required to neutralize = ?

Molarity of NaOH = 4.8 M

Volume of HCl = 20 mL

Molarity of HCl = ?

Solution:

Chemical equation:

HCl + NaOH    →   NaCl  + H₂O

In neutralization reaction the equal amount of  H⁺ from acid and OH⁻ from base react to form water and salt is also formed.

Formula:

M₁V₁ = M₂V₂

M₁ = molarity of NaOH

V₁ = Volume of NaOH

M₂ = molarity of HCl

V₂ = volume of HCl

Now we will put the values.

4.8 M × V₁ = 2 M × 29 mL

4.8 M × V₁ =58 M. mL

V₁ = 58 M. mL / 4.8 M

V₁ = 12.1 mL