What volume of 9.0 M sodium hydroxide must be used to prepare 1.2 L of a 1.0 M sodium hydroxide solution? *

0.13 L

Explanation:

Given data:

Initial volume of NaOH = ?

Initial molarity = 9.0 M

Final molarity = 1.0 M

Final volume = 1.2 L

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume

M₂ = Final molarity

V₂ = Final volume

now we will put the values in formula.

9.0 M × V₁ = 1.0 M × 1.2 L

9.0 M × V₁ = 1.2 M.L

V₁  =  1.2 M.L/ 9.0 M

V₁  =  0.13 L

0.13 L of 9.0 molar solution of NaOH must be used to make 1.2 L of 1.0M solution.

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