2Na+Cl 2 →2NaCl2, start text, N, a, end text, plus, start text, C, l, end text, start subscript, 2, end subscript, right arrow, 2, start text, N, a, C, l, end text How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start text, space, g, end text of \text{Na}Nastart text, N, a, end text and 23.0 \text{ g}23.0 g23, point, 0, start text, space, g, end text of \text{Cl}_2Cl 2 start text, C, l, end text, start subscript, 2, end subscript?

The mass of produced is, 45.8 grams.

Explanation : Given,

Mass of = 18.0 g

Mass of = 23.0 g

Molar mass of = 23 g/mol

Molar mass of = 71 g/mol

Molar mass of = 58.5 g/mol

First we have to calculate the moles of and .

and,

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

From the balanced reaction we conclude that

As, 2 mole of react with 1 mole of

So, 0.783 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 2 mole of react to give 2 mole of

So, 0.783 mole of react to give 0.783 mole of

Now we have to calculate the mass of

Therefore, the mass of produced is, 45.8 grams.