Calculate the energy absorbed when 6.20 g of aluminum is heated from 10.0°C to 65.0°C if the specific heat of aluminum is 0 .900 J/g°C

The energy absorbed when 6.20 grams of aluminum is heated from 10.0°C to 65.0°C is 306.9 Joules.

Explanation:

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

: Initial and final temperature of the substance

We have mass of aluminium = m = 6.20 g

Specific heat of aluminium= c = 0.900 J/g°C

Initial and final temperature of the aluminium

Final temperature of the aluminium =

Heat absorbed by the aluminium:

The energy absorbed when 6.20 grams of aluminum is heated from 10.0°C to 65.0°C is 306.9 Joules.

43.452

step-by-step explanation:

284 times .153 = 43.452

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml