What is the mass of 0.12 mol of mg(no3)2?
show your work.

17.796 g

Explanation: Molar masses of the given elements:

mMg= 24.3 g/mol

mN=14 g/mol

mO=16 g/mol

molar mass of Mg(NO3)2:

mMg(NO3)2= 24.3+(14+3*16)*2

mMg(NO3)2=148.3 g/mol

To calculate the mass of 0.12 mol of Mg(NO3)2 we multiply the molar mass by the number of moles:

mass=0.12mol*148.3 g/mol

mass=17.796 g

c) always accurate

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messi

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.