How many grams of O2 are needed to react with 13.6 g of NH3

Mass = 32 g

Explanation:

Given data:

Mass of O₂ needed = ?

Mass of NH₃ react = 13.6 g

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O

Number of moles of ammonia:

Number of moles = mass/ molar mass

Number of moles = 13.6 g/ 17 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of ammonia and oxygen from balance chemical equation.

                         NH₃          :            O₂

                           4            :               5

                          0.8          :         5/4×0.8 = 1

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 1 mol × 32 g/mol

Mass = 32 g

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.