What is the volume of a 0.120 M solution that contains 9.35 g of HCI?

2.13L

Explanation:

first you must find the amount(mols) of HCl in the solution. then you can use that to find the volume of the solution.

we know the:

mass m = 9.35g

molar mass M = 1 + 35.5=36.5 g/mol ( check periodic table )

concentration c = 0.120 mol/L

amount ( mols) of HCl:

n= m/M

n(HCl) = 9.35/36.5

= 0.2561644 mol

concentration of HCl in solution:

n= cV

V(HCl) = n/c

= 0.2561644/0.120

= 2.1347

= 2.13 L (3sf)

particle   p is an electron and particle q is a neutron