Write a balanced equation for the combustion of gaseous methane (CH4), a majority component of natural gas, in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water.

CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)

Explanation:

any combustion of a hydrocarbon equation is in form:

CₓHₐ(g) + BO₂(g) ---> YCO₂(g) + ZH₂O(g), where x,a,b,y,z are all whole number positive integers

there will be 1 CO₂ to 2 H₂O, since there is 1 C to 4 H in CH₄; it is not 1:4 since 2 H is needed in H₂O

CH₄(g) + _O₂(g) ---> 1CO₂ + 2H₂O

there is 4 total O on products side, which can make 2O₂

CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Explanation:

Step 1: Data given

gaseous methane = CH4(g)

Combustion reaction is adding O2. The products will be carbondioxide (CO2) and water vapor (H2O)

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount H on both sides, we have to multiply H2O by 2.

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 on the left side, by 2. Now the equation is balanced.

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

its pwirhfpiwe

explanation:

because dgjpwojefopjwp