What would be the temperature of 0.734 moles of chlorine gas be at 1.83 atmospheres in a 10.2 liter container? (r=0.0821 L·atm/mol·k)

310K

Explanation:

Since,

Pressure P = 1.83 atmospheres

Volume of chlorine gas V = 10.2L

Molar gas constant R = 0.0821 L.atm/mol.k)

Number of moles = 0.734 moles

Temperature T(in Kelvin) = ?

Apply ideal gas equation (pV = nRT)

1.83atm x 10.2L= 0.734 moles x 0.0821 L.atm/mol.k x T

18.67 = (0.06026 x T)

T = (18.67 / 0.06026)

T = 310K

Therefore, the new temperature of the chlorine gas is 310K

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.