Approximately 0.5 M KOH by diluting 20 mL of 6 M KOH into the appropriate volume of distilled water. You may use a 100-mL graduated cylinder repeatedly to reach your final volume. Show your calculations here: Final volume: (Store this solution in the provided bottle; label the bottle with your name and "0.5M KOH") b. Approximately 0.5 M HCI by diluting 5 mL of 6 M HCI into the appropriate volume of distilled water. You may use a 100-mL graduated cylinder to me It doesn't need to be exact. Show your calculations here: Final volume: c. Put enough solid NaCI to cover the bottom curve of a large test tube. Dissolve in about 15 mL of distilled water. 47

the answer is b. dilution

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

the objects have the same charge is correct.

nathan lee