Wednesday, April 1 st , 2020. Complete the following using the first eight slides from Ionic Compound Power Point. Group 1A has an oxidation number of +1 the name of this group isAlkali metals. Group 2A has an oxidation number of +2 the name of this group isAlkaline Earth metals. Group 3A has an oxidation number of +3 the name of this group isBoron group. Group 4A has an oxidation number of +4 the name of this group iscarbon group. Group 5A has an oxidation number of -3 the name of this group isnitrogen group. Group 6A has an oxidation number of -2 the name of this group isoxygen group. Group 7A has an oxidation number of -1 the name of this group ishalogens. Group 8A has an oxidation number of 0 the name of this group isnoble gases. Write the oxidation number for the following elements: 1. K +1: 2. Ne 0: 3. Si +4: 4. Ba +2: 5. Fr +1: 6. Be +2: 7. Nh +3: 8. Ar 0: 9. S -2: 10. C +4: 11. B +3: 12. Pb +4: 13. P -3: 14. O -2: 15. Cl -1:

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.