Based on Table I, what is the AH value for the production of 1.00 mole of NO2(g) from its elements at
101.3 kPa and 298 K?
1) +33.2 k) 2) -33.2 kJ 3) +132.8 kJ 4) -132.8 kJ

ANSWER: 33.2 kJ

EXPLANATION: This is the heat required to produce two moles of NO2(g). Therefore, it would only require half the amount, or 33.2 kj, to produce just one mole.

a is the answer to this question

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml