1 message These images represent the first-order reaction A → B initially and at some later time. The rate law for the reaction is Rate = 0.010 s−1 [A]. How much time has passed between the two images?a. 60 sb. 116 sc. 69 sd. 12.5 s

b. 116 sec

Explanation:

first order reaction A = A₀ * e^-kt

Given: K = 0.010 s⁻¹

here, A = 5 and A₀ = 16

5 = 16 * e^-0.010t

t = 116.31 s

Therefore, the time taken is approximately 116 seconds

the answer is definitely c.

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explanation: