How many moles of Al can be produced from 10.87 g of Ag?

Al (No3) 3(s) + 3Ag -> Al + 3AgNo3

0.91g of Al

Explanation:

Al(NO3)3(aq) + 3Ag(s) -> Al + 3Ag(NO3)

We check and we see that the given reaction equation is balanced

Now, from the equation, 3 moles of Ag reacts to produce 1 mole of Al

Mole ratio is 3:1

Number of moles = mass/molar mass

Molar mass of Ag ~ 108g/mol

3 moles of Ag = m/108g/mol

m = 3 moles of Ag × 108g/mol

m= 324g

1 mole of Al = 27g

Therefore, 324g of Ag produces 27g of Al,

10.87g of Ag will produce [(10.87g×27g)/324g] of Al

= 0.91g of Al

quartz

explanation: