How many moles of NaCl are in 2,719 mL of a 6.32 M solution?

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

Explanation:

We have:

Molarity of the NaCl solution = 6.32 M

Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L

1 mL = 0.001 L

Let the moles of NaCl be n.

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.