Un investigador observa dos plantas de la misma especie, pero con diferentes adaptaciones. Las plantas A tienen hojas color verde, raíces muy profundas con vellosidades de mucha densidad. Las plantas B, por el contrario, tiene raíces muy poco profundas, la densidad de sus vellosidades es menos densa, aunque el color de las hojas es igual. ¿Qué explicación puede dar el investigador en cuanto a que el color de las hojas de ambas plantas no haya cambiado?

The explanation that the researcher can give for the fact that the color of the leaves of both plants has not changed is that receive the same radiation from the sun .

Explanation:

English:

A researcher observes two plants of the same species, but with different adaptations. Plants A have green leaves, very deep roots with very dense hairs. Plants B, on the other hand, have very shallow roots, the density of their villi is less dense, although the colour of the leaves is the same. What explanation can the researcher give for the fact that the colour of the leaves of both plants has not changed?

Option for this question:

The coloration of leaves in plants depends on the interaction of sunlight with photosynthetic pigments, such as chlorophyll, found in their leaves.

From the idea that both plants are of the same species, it can be inferred that both have the same composition of photosynthetic pigments in their leaves, the amount of sunlight they receive being the factor that makes them have the same coloration, without changes.

The adaptations they possess and which differentiate them are the roots, which are responsible for the absorption of water and nutrients from the soil, which does not influence the color of the leaves.

Learn more:

Photosynthesis in a leaf

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm