Suppose you place 125 g of aluminum in a calorimeter with 1,000 g of water. The water changes temperature by 2 °C and the aluminum changes temperature by –74.95 °C.

Water has a known specific heat capacity of 4.184 J/g °C. Use the specific heat equation to find out how much heat energy the water gained (q).

The amount of heat gained by the water is 8368 J

Explanation:

To calculate the amount of heat absorbed, we use the equation:

where,

q = amount of heat absorbed = ?

m = mass of water = 1000 g

C = specific heat capacity of water = 4.184 J/g°C

= change in temperature = 2°C

Putting all the values in above equation, we get:

Hence, the amount of heat gained by the water is 8368 J

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: