What mass in grams of SO2 is needed to react with 37.50 mol of Oz?
2 SO2 + O2 + 2 H2O → 2 H2SO4
Show your work

4804.5 g of SO₂ are needed to the reaction

Explanation:

The reaction to produce sulfuric acid is:

2SO₂ + O₂ + 2H₂O →  2H₂SO₄

Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide in order to react. We can propose this rule of three.

If 1 mol of O₂ react to 2 moles of SO₂

Then, 37.50 moles of O₂ will react with (37.5 . 2) /1 = 75 moles of SO₂

We convert the moles to mass, to know the

75 mol . 64.06 g / 1 mol = 4804.5 g of SO₂

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.