1. At what temperature would 3.67 mole P2O3 gas occupy 67.5 L if the pressure is 115
kPa?

The answer for the following question is explained below.

Explanation:

Given:

no of moles (n) = 3.67 moles

volume of the gas (V) = 67.5 liters

pressure of the gas (P) = 115 k Pa

To solve:

Temperature of the gas (T)

We know;

P × V = n × R × T

Where;

P is pressure of the gas

V is the volume of the gas

n is the no of the moles

R is the universal gas constant

here the value of R(universal gas constant ) is 8.314 k Pa./mole.K

We know;

115 × 67.5 = 3.67 × 8.3145 × T

T =  

T =

T = 254.39 K

Therefore the temperature that is require to fill the gas is 254.3 K

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

sure im new too!

explanation: