Each of the two drums and connected hubs of 8-in. radius weighs 225 lb and has a radius of gyration about its center of 23 in. Calculate the magnitude of the angular acceleration of each drum. Friction in each bearing is negligible.

The magnitude of the angular acceleration of each drum is .

Explanation:

We know that,

where,   r = hub radius,        M = mass of the drum,

             K = radius of gyration,     = angular gyration

                T = ........ (1)

Now,  

         23 lb - T = m()

                 23 =

Therefore, we can conclude that the magnitude of the angular acceleration of each drum is .

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

particle   p is an electron and particle q is a neutron