H2(g) + Br2(l) ⇄ 2HBr(g) Kc = 4.8 × 108
Assume initial conditions of 0.400 M H2(g) and e...
Chemistry, 01.04.2020 20:16 CHRONICxDJ
H2(g) + Br2(l) ⇄ 2HBr(g) Kc = 4.8 × 108
Assume initial conditions of 0.400 M H2(g) and excess Br2(l). What is the equilibrium concentration of H2(g)?
Answers: 1
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