The information below describes a redox reaction. 3 equations: First: upper A g superscript plus (a q) plus upper A l (s) right arrow upper A g (s) plus upper A l superscript 3 plus (a q). Second: upper A G superscript plus (a q) plus e superscript minus right arrow upper A g (s). Third: upper A l (s) right arrow upper A l Superscript 3 plus (a q) plus 3 e superscript minus. What is the coefficient of silver in the final, balanced equation for this reaction? 1 2 3 4

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

can you list the answers so i can answer

2b2t

explanation:

2b2t