In a lab, 2.20 L of gas is collected over water at a temperature of 30 degrees C and a total pressure of 735.43 mmHg. Find the volume that the dry nitrogen of gas would occupy at STP.

Volume of nitrogen at STP  = 1.92 L

Explanation:

Given data:

Initial volume of gas = 2.20 L

Initial temperature = 30°C (30+273 = 303 k)

Initial pressure = 735.43 mmHg (735.43/760 = 0.97 atm)

Final volume = ?

Final pressure = 1 atm

Final temperature = 273 K

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 0.97 atm × 2.20 L × 273 K / 303 K × 1 atm

V₂ = 582.58 atm .L. K / 303 K.atm

V₂ = 1.92 L

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.