A party balloon was inside a store where the temperature was 27 °C. It had a volume of 2.3 L. The balloon was
taken out of the store, where the temperature outside is -3 °C. What is the volume of the balloon now?

2.07L

Explanation:

Data obtained from the question include:

T1 (initial temperature) = 27 °C = 27 + 273 = 300K

V1 (initial volume) = 2.3 L

T2 (final temperature) = - 3 °C = - 3 + 273 = 270K

V2 (final volume) =?

Using V1/T1 = V2/T2, the final volume of the balloon can be obtained as follow:

V1/T1 = V2/T2

2.3/300 = V2/270

Cross multiply to express in linear form.

300 x V2 = 2.3 x 270

Divide both side by 300

V2 = (2.3 x 270)/300

V2 = 2.07L

Therefore, the new volume of the balloon is 2.07L

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

2b2t

explanation:

2b2t