Pure chlorine gas at 1 atm is contained in a 195 cm3 bulb from which a 1-mm ID capillary 12 cm long leads to the atmosphere. The concentration of chlorine gas in the bulb can be assumed to be uniform at any time. The concentration of chlorine at the top of the capillary is essentially zero. How long will it take for the mole fraction of chlorine in the bulb to fall to 0.10 at 20 C

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Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.