The following data are obtained for the decomposition of N2O5 at a certain temperature: 2N2O5(g) ↔ 4NO2(g) + O2(g) Time(s) 0 200 400 600 800 N2O5 (atm) 2.70 2.41 2.15 1.92 1.71 Find the rate constant kobs for this first-order decomposition reaction. (Enter in sec-1)

K = 0.0003 s⁻¹

Explanation:

The reaction is

2N₂O₅ = 4NO₂ + O₂

The equilibrium is

a plot is attached

From the plot, the slope is -0.0006

-2 * K = -0.0006

K = 0.0003 s⁻¹

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

16

explanation:

the marks go by 4s