We have an aqueous solution that contains 23% (by mass) of a hypothetical solute Z. The formula weight of the solute Z is 139 g/mol. The density of the solution is observed to be 1.3 g/mL. What is the molarity of Z in this solution

The molar concentration of Z in the solution is 2.15 M

Explanation:

We are given:

23% (w/w) Z in solution

This means that 23 grams of Z is present in 100 grams of solution

To calculate the volume of solution, we use the equation:

Density of solution = 1.3 g/mL

Mass of solution = 100.0 g

Putting values in above equation, we get:

To calculate the molarity of solution, we use the equation:

Given mass of Z = 23 g

Molar mass of Z = 139 g/mol

Volume of solution = 76.92 mL

Putting values in above equation, we get:

Hence, the molar concentration of Z in the solution is 2.15 M

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.