Consider the reaction: 2 Al + 3Br2 → 2 AlBr3 Suppose a reaction vessel initially contains 5.0 mole Al and 6.0 mole Br2. What is in the reaction vessel once the reaction has occurred to the fullest extent possible? chapter 9

4 moles of and 1 mole of will be present in the reaction vessel

Explanation:

The reaction given in the question is

⇒

According to the stoichiometric coefficients of the reaction, 2 moles of requires 3 moles of so in this reaction, is a limiting reagent. So we will consider that is in excess.

Now,

Since 3 moles of requires 2 moles of

So, for 6 moles of the moles of required = = 4 moles.

Moles of remaining after the completion of reaction = 5 - 4 = 1 mole.

Again,

Since 3 moles of produces 2 moles of

So, moles of produced by 6 moles of = = 4 moles.

Therefore, after the completion of reaction, 4 moles of and 1 mole of will be present in the reaction vessel.

the answer is the first option

explanation:

just googled it m8. not that hard

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