A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the reactant is 0.360 mol/L, how long will it take for the concentration to become 0.180 mol/L?

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

where,

k = rate constant =

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

= Initial concentration = 0.360 mol/L

Putting values in above equation, we get:

Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s

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