Arrange the following aqueous solutions in order of decreasing freezing point: 0.10 m Na3PO4, 0.35 m NaCl, 0.20 m MgCl2, 0.15 m C6H12O6, 0.15 m CH3COOH. (Introduce only the formulas, not the concentrations, of each substance in the appropriate box, beginning with the highest freezing point. Click in the answer boxes to activate the palette.) > > > > highest freezing point lowest freezing point

0.35 m > 0.20 m >0.10 m > 0.15 m > 0.15 m

Explanation:

Depression in freezing point:

where,

= freezing point of solution

= freezing point of solvent

= freezing point constant

m = molality

1. For 0.10 m

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be

2. For 0.35 m

, i= 2 as it is a electrolyte and dissociate to give 2 ions. and concentration of ions will be  

3. For 0.20 m

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be  

4. For 0.15 m

, i= 1 as it is a non electrolyte and does not dissociate to give ions.

5. For 0.15 m

, i= 2 as it is a electrolyte and dissociate to give 2 ions and thus have  

As concentration is highest for 0.35 m , freezing point depression will be highest and thus has lowest freezing point. As concentration is lowest for 0.15 m , freezing point depression will be lowest and thus has highest freezing point