A 1.78−L sample of hydrogen chloride (HCl) gas at 2.09 atm and 22°C is completely dissolved in 699 mL of water to form hydrochloric acid solution. Calculate the molarity of the solution. Assume no change in volume.

Explanation:

Hello,

In this case, it is firstly necessary to compute the dissolved moles of hydrogen chloride into the water as shown below:

Thus, the molarity is computed as shown below:

Wherein no change in volume is considered, therefore the volume of the solution was the same volume of water.

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58750.08068 is the answer i think

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