A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine the volume of the sample of CO2(g) if the temperature and pressure are changed to 336 K and 152.0 kPa.

The final volume of the sample of gas = 0.000151

Explanation:

Initial volume = 200 ml = 0.0002

Initial temperature = 296 K

Initial pressure = 101.3 K pa

Final temperature = 336 K

Final pressure =  K pa

Relation between P , V & T is given by

Put all the values in the above equation we get

= 0.000151

This is the final volume of the sample of gas.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'