Consider the balanced equation for the following reaction:
3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq)
Determine the theoretical yield of LiClO3(aq) in grams if the percent yield of LiClO3(aq) is 81.0% and 9.45 moles of LiClO3(aq) forms.

The theoretical yield of the lithium chlorate is 1054.67 grams

Explanation:

To calculate the mass for given number of moles, we use the equation:

Actual moles of lithium chlorate = 9.45 moles

Molar mass of lithium chlorate = 90.4 g/mol

Putting values in above equation, we get:

To calculate the theoretical yield of lithium chlorate, we use the equation:

Actual yield of lithium chlorate = 854.28 g

Percentage yield of lithium chlorate = 81.0 %

Putting values in above equation, we get:

Hence, the theoretical yield of the lithium chlorate is 1054.67 grams

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