Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid. Part A Write chemical equations for first ionization step of carbonic acid. Express your answer as a chemical equation. Identify all of the phases in your answer. nothing Request Answer Part B Complete previous part(s) Part C Write chemical equations for second ionization step of carbonic acid. Express your answer as a chemical equation. Identify all of the phases in your answer. nothing

The chemical equations and equilibrium constant expression for each ionization steps is written below.

Explanation:

The chemical formula of carbonic acid is . It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water

The chemical equation for the first dissociation of carbonic acid follows:

The expression of first equilibrium constant equation follows:

The chemical equation for the second dissociation of carbonic acid follows:

The expression of second equilibrium constant equation follows:

Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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