A sample of carbon monoxide gas has a volume of
3.45 L and a pressure of 2.82 atm, under a
constant temperature of 28 "C. What is the new
volume, if the pressure is increased to 4.2 atm?

2.3L

Explanation:

Given that:

Volume of carbon monoxide gas V1 = 3.45L

Temperature T1 = 28°C

Convert Celsius to Kelvin

(28°C + 273 = 301K)

Pressure P1 = 2.82 atm

Final Volume V2 = ?

Final temperature T2 = 28°C = 301K

Final pressure = 4.2atm

Then, apply the general gas equation

(P1V1)/T1 = (P2V2)/T2

(2.82 x 3.45)/301 = (4.2 x V2)/301

9.73/301 = 4.2V2/301

0.032 = 0.014V2

To get the value of V2, divide both sides by 0.014

0.032/0.014 = 0.014V2/0.014

2.286 = V2

Rounded to nearest tenth, V2 becomes 2.3L

Thus, the new volume of the carbon monoxide gas is 2.3 liters

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation: