When the equation below is balanced with the smallest possible integer coefficients, what is the coefficient for PH3?

P2H4(g) PH3(g) + P4(s)

a. 2
b. 4
c. 6
d. 8
e. 12

The coefficient for PH3 is 8. Option D is correct.

Explanation:

Step 1: The unbalanced equation

P2H4(g) ⇆ PH3(g) + P4(s)

Step 2: Balancing the equation

P2H4(g) ⇆ PH3(g) + P4(s)

On the left side we have 4x H (in P2H4), on the right side we have 3x H (in PH3). To balance the amount of H on both sides, we have to multiply P2H4 on the left side by 3 and PH3 on the right by 4.

3P2H4(g ) ⇆ 4PH3(g) + P4(s)

On the left side we have 6x P (in 3P2H4) on the right side we have 8x P (4x in 4PH3 and 4x in P4). To balance the amount of P on bot hsides, we have to multiply 3P2H4 by 2 and 4PH3 also by 2. Now the equation is balanced

6P2H4(g ) ⇆ 8PH3(g) + P4(s)

The coefficient for PH3 is 8. Option D is correct.

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c. orbital shape i hope this is correct