Explanation:
1)
Given data:
Moles of Al(OH)₃ = 0.52 mol
Moles of HCl consume = ?
Solution:
Chemical equation:
Al(OH)₃ + 3HCl    →   AlCl₃ + 3H₂O
Now we will compare the moles of HCl and Al(OH)₃.
            Al(OH)₃     :      HCl
              1         :       3
             0.52       :       3×0.52 = 1.56 mol
1.56 moles of HCl are consumed with 0.52 moles of  Al(OH)₃ .
2)
Given data:
Moles of water  produced = ?
Moles of Al(OH)₃ react = 1.35 mol
Solution:
Chemical equation:
Al(OH)₃ + 3HCl    →   AlCl₃ + 3H₂O
Now we will compare the moles of H₂O and Al(OH)₃.
            Al(OH)₃     :      H₂O
              1         :       3
             1.35        :       3×1.35 = 4.05 mol
4.05 moles of H₂O are produced from 1.35 moles of  Al(OH)₃ .
3)
Given data:
Moles of water  produced = ?
Moles of HCl react = 1.98 mol
Solution:
Chemical equation:
Al(OH)₃ + 3HCl    →   AlCl₃ + 3H₂O
Now we will compare the moles of Hâ‚‚O and HCl.
               HCl      :      H₂O
               3        :       3
              1.98      :       1.98
1.98 moles of H₂O are produced from 1.98 moles of  HCl.
4)
Given data:
Moles of Al(OH)₃ required = ?
Moles of HCl react = 65 mol
Solution:
Chemical equation:
Al(OH)₃ + 3HCl    →   AlCl₃ + 3H₂O
Now we will compare the moles of HCl  and Al(OH)₃.
               HCl      :      Al(OH)₃
               3        :        1
               65       :       1/3×65 = 21.67 mol
65 moles of HCl  react with 21.67 moles of Al(OH)₃.
5)
Given data:
Moles of iron produced = 5.61 mol
Moles of CO required = ?
Solution:
Chemical equation:
Fe₂O₃  + 3 CO  →   2Fe  + 3CO₂
Now we will compare the moles of iron and CO.
             Fe     :     CO
              2      :     3
             5.61    :   3/2×5.61 = 8.4 mol
For the production of 5.61 moles of Fe 8.4 moles of Co are required.
6)
Given data:
Moles of CO react = 16.8 mol
Moles of Fe₂O₃ required = ?
Solution:
Chemical equation:
Fe₂O₃  + 3 CO  →   2Fe  + 3CO₂
Now we will compare the moles of Fe₂O₃  and CO.
             CO     :    Fe₂O₃
               3      :      1
             16.8     :   1/3×16.8= 5.6 mol
5.6 moles of Fe₂O₃  required to react with 16.8 moles of CO.
7)
Given data:
Moles of COâ‚‚ produced = 32.5 mol
Moles of Fe produced  = ?
Solution:
Chemical equation:
Fe₂O₃  + 3 CO  →   2Fe  + 3CO₂
Now we will compare the moles of Fe  and CO₂.
             CO₂     :    Fe
               3      :      2
             32.5     :   2/3×32.5= 21.67 mol
when 32.5 moles of COâ‚‚ are produced 21.67 moles of iron also produced.