How many moles of oxygen will be produced from the decomposition of 3 moles of KClO3?

Equation: __KClO3 --> __KCl + O2

4.5 moles of oxygen will be produced from the decomposition of 3 moles of KClO3.

The balanced chemical equation of the decomposition of pottasium chlorate (KClO3) is given as follows:

2KClO3 → 2KCl + 302

According to this equation, 2 moles of KClO3 decomposes to form 2 moles of KCl and 3 moles of O2.

If 3 moles of KClO3 is decomposed, (3 × 3)/2 = 4.5moles of O2 will be produced.

Therefore, 4.5 moles of oxygen will be produced from the decomposition of 3 moles of KClO3.

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4.5moles

Explanation:

First, let us balance the equation given from the question. This is illustrated below:

KClO3 —> KCl + O2

There are 2 atoms of O on the right side and 3 atoms on the left. It can be balance by putting 2 in front of KClO3 and 3 in of O2 as shown below

2KClO3 —> KCl + 3O2

Now, we have 2 atoms each of K and Cl on the left side and 1atom each of K and Cl on the right. It can be balance by putting 2 in front of KCl as shown below:

2KClO3 —> 2KCl + 3O2

Now the equation is balanced.

From the balanced equation,

2 moles of KClO3 produced 3 moles of O2.

Therefore, 3 moles of KClO3 will produce = (3 x 3) /2 = 4.5moles of O2.

Therefore 3 moles of KClO3 will produce 4.5 moles of O2

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