How many grams of I2 (iodine) are produced by the reaction of 0.360 mol of
CuCl2 according to the following equation?
2 CuCl2 + 4 KI => 2 Cul + 4 KI +I2

45.7
58.6
22.8
91.4

A. 45.7

Explanation:

2 CuCl₂ + 4 KI => 2 Cul + 4 KI +I₂

2 mol of CuCl₂ for every 1 mol of I₂ (look at coefficients in balanced equation)

0.360 mol CuCl₂ * 1 mol I₂ / 2 mol CuCl₂ = 0.180 mol I₂

molar mass of I₂ = 2(126.904) = 253.808 g/mol I₂

0.180 mol I₂ * 253.808 g I₂/mol I₂  = 45.685 g I₂

u i forgot the answer?

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.